c
(c) Mass of silver salt taken = \(0.228\, gm\)

Mass of silver left = \( 0.162 \,gm\)

Basicity of acid = \(2\)

Step \(1 -\) To calculate the equivalent mass of the silver salt \((E)\)

\(\frac{{{\rm{Eq}}{\rm{.}}\,\,{\rm{mass}}\,\,{\rm{of}}\,\,{\rm{silver}}\,\,{\rm{salt}}}}{{{\rm{Eq}}{\rm{.}}\,\,{\rm{mass}}\,\,{\rm{of}}\,\,{\rm{silver}}}} = \frac{{{\rm{Mass}}\,\,{\rm{of}}\,\,{\rm{Acid}}\,\,{\rm{taken}}}}{{{\rm{Mass}}\,\,{\rm{of}}\,\,{\rm{silver}}\,\,{\rm{left}}}}\)

\( \frac{E}{{108}} = \frac{{0.228}}{{0.162}}\)

\( E = \frac{{0.228}}{{0.162}} \times 108 = 152\,({\rm{Eq}}{\rm{.}}\,\,{\rm{mass}}\,\,{\rm{of}}\,\,{\rm{silver}}\,\,{\rm{salt)}}\)

Step \(2\) -To calculate the eq. mass of acid.

Eq. mass of acid = Eq. mass of silver salt -Eq. mass of \(Ag\) + Basicity

= \(152 -108 + 1 = 152 -109 = 43\) (Eq. mass of acid)

Step \(3 -\) To determine the molecular mass of acid.

Mol. mass of the acid = Eq. mass of acid \(\times\) basicity = \(45 \times 2 = 90\)