MCQ
જો $3({\sec ^2}\theta + {\tan ^2}\theta ) = 5$, તો $\theta $ નો વ્યાપક ઉકેલ મેળવો.
- A$2n\pi + \frac{\pi }{6}$
- B$2n\pi \pm \frac{\pi }{6}$
- ✓$n\pi \pm \frac{\pi }{6}$
- D$n\pi \pm \frac{\pi }{3}$
also ${\sec ^2}\theta - {\tan ^2}\theta = 1$
$ \Rightarrow $ ${\tan ^2}\theta = \frac{1}{3} = {\tan ^2}\left( {\frac{\pi }{6}} \right) $
$\Rightarrow \theta = n\pi \pm \frac{\pi }{6}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.