જો ${{3x + a} \over {{x^2} - 3x + 2}} = {A \over {(x - 2)}} - {{10} \over {x - 1}}$, તો
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d
(d) \({{3x + a} \over {{x^2} - 3x + 2}} = {A \over {(x - 2)}} - {{10} \over {(x - 1)}}\)
(d) \({{3x + a} \over {{x^2} - 3x + 2}} = {A \over {(x - 2)}} - {{10} \over {(x - 1)}}\)
==> \((3x + a) = A(x - 1) - 10(x - 2)\)
==> \(3 = A - 10\), \(a = - A + 20\)
(On equating coefficients of \(x\) and constant term)
==> \(A = 13, a = 7.\)
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