$|B|=\begin{vmatrix} \mathbf{2} & \mathbf{1} \\ \mathbf{-1} & \mathbf{2} \end{vmatrix} =4+1=5$ 
$0$
$\therefore B^{-1}$ નું અસ્તિત્વ છે.
$\therefore adj B=\begin{bmatrix}2 & -1 \\1 & 2 \end{bmatrix}$
$\therefore B^{-1}=\frac{1}{|B|}adj B=\frac{1}{5}\begin{bmatrix}2 & -1 \\1 & 2 \end{bmatrix}$
$AB=\begin{bmatrix}2 & 2 \\2 & 5 \end{bmatrix}\begin{bmatrix}2 & 1 \\-1 & 2 \end{bmatrix}=\begin{bmatrix}2 & 6 \\-1 & 12 \end{bmatrix}$
$B^{-1}AB=\frac{1}{5}\begin{bmatrix}2 & -1 \\1 & 2 \end{bmatrix}\begin{bmatrix}2 & 6 \\-1 & 12 \end{bmatrix}$
$=\frac{1}{5}\begin{bmatrix}4+1 & 12-12 \\2-2 & 6+24 \end{bmatrix}$
$=\frac{1}{5}\begin{bmatrix}5 & 0 \\0 & 30 \end{bmatrix}$
$B^{-1}AB=\begin{bmatrix}1 & 0 \\0 & 6 \end{bmatrix}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.