જો $A=\left(\begin{array}{ll}{2} & {2} \\ {9} & {4}\end{array}\right)$ અને $I=\left(\begin{array}{ll}{1} & {0} \\ {0} & {1}\end{array}\right),$ હોય તો $10 A^{-1}$ મેળવો.
JEE MAIN 2020, Difficult
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$A=\left(\begin{array}{ll}{2} & {2} \\ {9} & {4}\end{array}\right) ;|A|=8-18=-10$
$A^{-1}=\frac{\operatorname{adj} A}{|A|}=\frac{\left(\begin{array}{cc}{4} & {-2} \\ {-9} & {2}\end{array}\right)}{-10}$
$10 \mathrm{A}^{-1}=\left(\begin{array}{cc}{-4} & {2} \\ {9} & {-2}\end{array}\right)=\mathrm{A}-6 \mathrm{I}$
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