MCQ
જો $A=tan^{-1}x$ હોય તો $sin2A=...........$
- A$\frac{2x}{{1-{{x}^{2}}}}$
- B$\frac{2x}{\sqrt{1-{{x}^{2}}}}$
- ✓$\frac{2x}{1+{{x}^{2}}}$
- Dએકપણ નહીં
$A = tan^{-1}x$
$\therefore \ = tan A$
અહી, $sin 2A = \frac{2 tanA}{1 + tan^2 A}$
$sin 2A = \frac{2x}{1 + x^2}$
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