$f(x)=\left\{\begin{array}{ll} \min \left\{(x+6), x^{2}\right\}, & -3 \leq x \leq 0 \\ \max \left\{\sqrt{x}, x^{2}\right\}, & 0 \leq x \leq 1 \end{array}\right.$ આપેલ છે.
જો $y = f ( x )$ અને $x$ -અક્ષ દ્વારા આવૃત પ્રદેશનું ક્ષેત્રફળ $A$ હોય તો $6 A$ ની કિમંત મેળવો.
$f ( x )=\left\{\begin{array}{ll}\min \left\{( x +6), x ^{2}\right\} & ,-3 \leq x \leq 0 \\ \max \left\{\sqrt{ x }, x ^{2}\right\} & , 0 \leq x \leq 1\end{array}\right.$
area bounded by $y = f ( x )$ and $x$ -axis
$=\int_{-3}^{-2}(x+6) d x+\int_{-2}^{0} x^{2} d x+\int_{0}^{1} \sqrt{x} d x$
$A =\frac{41}{6}$
$6 A =41$
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