MCQ
જો $\left| {\begin{array}{*{20}{c}}1&2&4\\2&x&5\\4&{ - 2}&1\end{array}} \right| = 0,$ તો $x=...... .$
- ✓$2$
- B$-2$
- C$\frac{14}{5}$
- D$-\frac{14}{5}$
બીજી હારને લઈને વિસ્તરણ કરતાં,
$-2(2+8)+x(1-16)-5(-2-8)=0$
$\therefore -20-15x+50=0$
$\therefore 30=15x$
$\therefore x=2$
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