નિર્બળ એસિડનું પ્રબળ બેઇઝ વડે તટસ્થીકરણ કરતાં, $HA + OH^- ⇌ A^- + H_2O$
તો $\,{\text{K}}\,\, = \,\,\,\frac{{\left[ {{{\text{A}}^{\text{ - }}}} \right]}}{{\left[ {HA} \right]\,\,\,\,\left[ {O{H^ - }} \right]}}\,\,\,.........\,\,(ii)$
$(i)$ ને $(ii)$ વડે ભાગતા,$\,\frac{{{{\text{K}}_{\text{a}}}}}{{\text{K}}}\,\, = \,\,\left[ {{H^ + }} \right]\,\left[ {O{H^ - }} \right]\,\, = \,\,{K_w}\,\,\,\,\,\,\,\therefore \,\,K\,\, = \,\,\frac{{{K_a}}}{{{K_w}}}\,\, = \,\,\frac{{{{10}^{ - 5}}}}{{{{10}^{ - 14}}}}\,\, = \,\,{10^9}$
[આપેલ : $\sqrt{2}=1.41$ ]