(\(i\))

\(C^{\prime}=\frac{\varepsilon_0 A}{d^{\prime}}, C=\frac{\varepsilon_0 A}{d}\)

\(d^{\prime}>d\)

\( C^{\prime}>C\)

Hence, final capacitance greater than initial capacitance,

(\(ii\))

\(U^{\prime}=\frac{1}{2} C^{\prime} V^2\)

\(U=\frac{1}{2} C V^2\)

\(U^{\prime}>U\)

Hence final energy is greater than initial energy

(\(iii\))

\(\frac{Q^{\prime}}{V^{\prime}}=C^{\prime} \text { and } \frac{Q}{V}=C\)

\(\frac{Q^{\prime}}{V^{\prime}} \neq \frac{Q}{V}\)

(\(iv\)) Product of charge and voltage

\(X^{\prime}=Q^{\prime} V=C^{\prime} V^2\)

\(X=Q V=C V^2\)

\(X^{\prime}>X\)