MCQ
જો ${({\tan ^{ - 1}}x)^2} + {({\cot ^{ - 1}}x)^2} = \frac{{5{\pi ^2}}}{8} $ તો $x =\ ..... . .. $
- ✓$-1$
- B$1$
- C$0$
- Dએકપણ નહીં.
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{જ્યા $x,y \in R^+, x^2y + x \ne 0$ }