\(E=150 \,V / m\)
\(R=6400 \,km\)
Using Gauss' Law
\(\Rightarrow E A=\frac{q}{\varepsilon_0}\)
\(\Rightarrow 150\left(4 \pi\left(6400 \times 10^3\right)^2\right)=\frac{q}{\varepsilon_0}\)
\(q=150 \times 4 \pi \times\left(6400 \times 10^3\right)^2 \times 8.854 \times 10^{-12}\)
\(q=6.8 \times 10^5 \,C\)
($\sin 37^{\circ}=\frac{3}{5}$ લો)