MCQ
જો $y = {x^{\sin x}},$ તો ${{dy} \over {dx}} = $
- ✓${{x\cos x.\log x + \sin x} \over x}.{x^{\sin x}}$
- B${{y[x\cos x.\log x + \cos x]} \over x}$
- C$y[x\sin x.\log x + \cos x]$
- Dએકપણ નહીં
$\therefore$ ${{dy} \over {dx}} = {x^{\sin x}}\left[ {\frac{{\sin x + x\cos x{{\log }_e}x}}{x}} \right]$.
$={{x}^{\sin x}}\left[ \frac{\sin x+x\cos x{{\log }_{e}}x}{x} \right]$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.