Hence, $0.01$ mole of $NaOH$ will be completely neutralised by $0.01$ mole of $HCL$.
$\Rightarrow\; NaOH$ left unneutralised $=0.1-0.01=0.09$ mol As equal volumes of two solutions are mixed,
$[\mathrm{OH}]^{-}=\frac{0.09}{2}=0.045 \mathrm{M} $
$ \Rightarrow \mathrm{pOH}=-\log (0.045)=1.35 $
$\therefore \mathrm{pH}=14-1.35=12.65$
| સંયોજન | $K_{sp}$ |
| $AgCl$ | $1.1\times10^{-10}$ |
| $AgI$ | $1.0\times10^{-16}$ |
| $PbCrO_4$ | $4.0\times10^{-14}$ |
| $Ag_2CO_3$ | $8.0\times10^{-12}$ |
સૌથી વધુ દ્રાવ્ય અને ઓછામાં ઓછા દ્રાવ્ય સંયોજનો અનુક્રમે છે.
[આપેલ : $\sqrt{2}=1.41$ ]