\(H_2S\) does not evolve as liberated \(H_2S\) is neutralized by \(NaOH\) and \(Na_2S\) is formed.
સ્તંભ $A$ | સ્તંભ $B$ |
$(i) \;\mathrm{Na}_{2} \mathrm{O}$ | $(a)$ તટસ્થ |
$(ii) \;\mathrm{Al}_{2} \mathrm{O}_{3}$ | $(b)$ બેઝિક |
$(iii)\;\mathrm{N}_{2} \mathrm{O}$ | $(c)$ એસિડિક |
$(iv)\;\mathrm{Cl}_{2} \mathrm{O}_{7}$ | $(d)$ ઉભયગુણી |