\(AlF _3\) shows trigonal symmetric structure due to \(sp ^2\) hybridization.
\(NF _3\) shows pyramidal geometry, having equal bonds due to \(sp ^3\)
\(ClF _3\) shows trigonal bi-pyramidal due to \(dsp ^3\) hybridization, in which all bonds are not equal.
Hence, \(ClF _3\) is the molecule whose bonds are not equal.
ઉપરોક્ત પ્રક્રિયામાં,
$X + {H_2}S{O_4} \to Y + BaS{O_4}$
$Y\xrightarrow[{\Delta \, > \,365\,K}]{\Delta }Z + {H_2}O + {O_2}$
$Y$ અને $Z$ શું હશે ?