\(v =\sqrt{\frac{ GM _{\odot}}{ r }}\)

\(L=m \sqrt{\frac{ GM _e}{ r }} \cdot r\)

\(L \propto r ^{\frac{1}{2}}\)

Now distance from centre is increased by \(8\) times.

So new distance from centre \(=r+8 r=9 r\)

Now angular momentum \(L^{\prime} \propto(9 r )^{1 / 2}\)

So new distance from centre \(=r+8 r=9 r\)

Now angular momentum \(L^{\prime} \propto(9 r)^{1 / 2}\)

\(\frac{L}{L^{\prime}}=\frac{ r ^{1 / 2}}{(9 r )^{1 / 2}}=\frac{1}{3}\)

\(L^{\prime}=3 L\)