\( = 50 - \frac{1}{2} \times 60 - \frac{3}{2} \times 40 \)
\(= 50 - 30 - 60 \)
\(= 50 - 90 = - 40\,J{K^{ - 1}}\,mol{e^{ - 1}}\)
સંતુલને \({{\Delta G}} = {\text{0 - 20}} \times {\text{1}}{{\text{0}}^{\text{3}}} = T \times - 40\)
\(T = \frac{{20 \times 1000}}{{40}} = 500\,\,\,Kelvin\)
$C _{2} H _{6} \rightarrow C _{2} H _{4}+ H _{2}$
પ્રકિયા એન્થાલ્પી $\Delta_{ r } H =...........{ kJ\, mol ^{-1}}$.
[આપેલ : બંધ એન્થાલ્પી $kJ$ $mol$ $^{-1}:C-C : 347, C = C : 611 ; C - H : 414, H - H : 436]$