\(\therefore a = \mu g\)

Now from equation of motion \({v^2} = {u^2} - 2as\)

\( \Rightarrow \;0 = {u^2} - 2as\)

\(⇒\) \(s = \frac{{{u^2}}}{{2a}} = \frac{{{u^2}}}{{2\mu \;g}}\)

\(\therefore s= \frac{{v_0^2}}{{2\mu \,g}}\)