\(\Rightarrow r \propto {v^2} \,\,\,\,(\theta \,= અચળ)\)
\(\frac{{{r_2}}}{{{r_1}}} = {\left( {\frac{{{v_2}}}{{{v_1}}}} \right)^2} = {\left( {\frac{{1.1v}}{v}} \right)^2} \,= 1.21\)
\(\Rightarrow r_2 = 1.21 \times \,r_1 \,= 1.21 \times \,20 = 24.2 \,m\)
આપેલ : $1\, {ly}=9.46 \times 10^{15} \,{m},$ $\, {AU}=1.5 \times 10^{11}\, {m}$