$ᴧ^{0} HOAC = ᴧ^{0} HCl + ᴧ^{0} NaOAC - ᴧ^{0} NaCl$
$= 426.2 + 91.0 - 226.5 = 290.7$
($Cu$નું આણ્વિય દળ $63.5\, amu$)
($F = 96,500\;C\;mo{l^{ - 1}}; \,\, R = 8.314\;J{K^{ - 1}}mo{l^{ - 1}})$
$Ni ( s )+2 Ag ^{+}(0.001 M ) \rightarrow Ni ^{2+}(0.001 M )+2 Ag ( s )$
$($ આપેલ છે $298\, K$ પર $E _{\text {cell }}^{\circ}=10.5 \,V , \frac{2.303 RT }{ F }=0.059)$