$10\left[ FeSO _4 \cdot\left( NH _4\right)_2 SO _4 \cdot 6 H _2 O \right]+2 KMnO _4+8 H _2 SO _4$
$\downarrow$
$5 Fe _2\left( SO _4\right)_3+2 MnSO _4+10\left( NH _4\right)_2 SO _4+ K _2 SO _4+68 H _2 O$
(પરમાણ્વીય ક્રમાંક: $Ni = 28, Ti = 22, $$Cr = 24, Co = 27$)