\(\therefore \ln M n O_{4}^{-},\) Mn has \(+7\) oxidation state having no electron in d-orbitals. It ts considered that higher the oxidation state of metal, greater is the tendency to occur \(L \rightarrow M\) charge transfer,
because ligand is able to donate the electron into the vacant ( - orbital of metal.
since, charge transfer is laporate as well as spin allowed, therefore, it shows colour
સ્તંભ $I$ | સ્તંભ $II$ |
$(a)$ કોપર | $(i)$ અધાતુ |
$(b)$ ફ્લોરિન | $(ii)$ સંક્રાંતિ ધાતુ |
$(c)$ સિલિકોન | $(iii)$ લેન્થનોઇડ |
$(d)$ સિરિયમ | $(iv)$ અર્ધધાતુ |
સાચી જોડ ઓળખો: