$2MnO_4^ - + 5{C_2}O_4^ - + 16{H^ + } \to 2M{n^{ + + }} + 10C{O_2} + 8{H_2}O$
અહી $20\, mL$ of $0.1\, M\, KMnO_4$ એ કોના બરાબર હશે
\(0.1\,M\,KMnO_4 = 0.5\,N\,KMnO_4\)
\(\therefore \) Meq of \(KMnO_4 = 20 \times 0.5 = 10\) (\(n\) factor \(= 5\))
Meq of \(50 \,ml\) of \(0.1\,M\,H_2C_2O_4 = 50 \times 0.2 = 10\)
\((0.1\,M\,H_2C_2O_4 = 0.2\,N\,H_2C_2O_4)\)