c
\(\begin{array}{l}
Give,\,p = {a^{1/2}}{b^2}{c^3}{d^{ - 4}},\\
Maximum\,relative\,error,\\
\frac{{\Delta p}}{p} = \frac{1}{2}\frac{{\Delta a}}{a} + 2\frac{{\Delta b}}{b} + 3\frac{{\Delta c}}{c} + 4\frac{{\Delta d}}{d}\\
 = \frac{1}{2} \times 2 + 2 \times 1 + 3 \times 3 + 4 \times 5\\
 = 32\% 
\end{array}\)