$\mathrm{C}_{7} \mathrm{H}_{8} \stackrel{3 \mathrm{Cl}_{2} / \Delta}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{Br}_{2} / \mathrm{Fe}}{\rightarrow} \mathrm{B} \stackrel{\mathrm{Zn} / \mathrm{HCl}}{\rightarrow} \mathrm{C}$
નીપજ '$C$' શોધો.
$C{H_3}C{H_2}C \equiv CH\, + \,HCl\, \to \,B\,\xrightarrow{{HI}}C$
$\begin{array}{*{20}{c}}
{C{H_3}}\\
{|\,\,\,\,\,}\\
{{C_6}{H_5}C{H_2} - C - C{H_2} - C{H_3}}\\
{|\,\,\,\,\,}\\
{Br\,\,\,}
\end{array}$ $\xrightarrow[{{C_2}{H_5}OH}]{{{C_2}{H_5}ONa}}$
$(1)$ $C{H_3}C{H_2}C{H_2}Cl + $ $\begin{array}{*{20}{c}}
{\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,|}
\end{array}} \\
{C{H_3} - C - {O^ - }} \\
{\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$ $(2)$ $C{H_3}C{H_2}C{H_2}I + $$\begin{array}{*{20}{c}}
{\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,|}
\end{array}} \\
{C{H_3} - C - {O^ - }} \\
{\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(3)$ $\begin{array}{*{20}{c}}
{{H_3}C - CH - C{H_3}} \\
{|\,\,\,\,} \\
{Br\,\,\,}
\end{array}$ $+CH_3O^-$ $(4)$ $\begin{array}{*{20}{c}}
{{H_3}C - CH - C{H_3}} \\
{|\,\,\,\,} \\
{Br\,\,\,}
\end{array}$ $+CH_3S^-$
${CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br} \xrightarrow[\Delta]{\mathrm{KOH}_{(a k)}} \mathrm{A} \xrightarrow{\mathrm{HBr}} \mathrm{B} \xrightarrow[\mathrm{KOH}_{(a) i}]{\Delta} \mathrm{C}$