$E_{cell}^ \circ \, = \,\,1.1\,\, - \,\,\frac{{0.059}}{2}\log \frac{{0.1}}{{0.1}}\,\, = \,\,1.10\,\,volt$
$(i)\, Cu^{2+} + 2e^- \rightarrow Cu\,,$ $ E^o = 0.337\, V$
$(ii)\, Cu^{2+} + e^- \rightarrow Cu^+\,,$ $ E^o = 0.153\, V$
તો પ્રક્રિયા $Cu^+ + e^- \rightarrow Cu$ માટે $E^o$........... $V$ થશે.