$(5 \lambda-10)-1(3 \lambda-5)+(6-5)=0$
$2 \lambda-10+5+1=0$
$\lambda=2$ only one option satisfy
Atleast one If $\mathrm{D}_{1}, \mathrm{D}_{2}, \mathrm{D}_{3} \neq 0$
$A = \left[ {\begin{array}{*{20}{c}}
{{{10}^{30}} + 5}&{{{10}^{20}} + 4}&{{{10}^{20}} + 6}\\
{{{10}^4} + 2}&{{{10}^8} + 7}&{{{10}^{10}} + 2n}\\
{{{10}^4} + 8}&{{{10}^6} + 4}&{{{10}^{15}} + 9}
\end{array}} \right]$ , $n \in N$, હોય તો . ..
$A\left[ {\begin{array}{*{20}{c}}
1&2&3 \\
0&2&3 \\
0&1&1
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
0&0&1 \\
1&0&0 \\
0&1&0
\end{array}} \right]$
તો $A^{-1}$ મેળવો.