$\left(\mathrm{hc}=1240\; \mathrm{eV} \mathrm{nm}, 1\; \mathrm{eV}=1.6 \times 10^{-19} \;\mathrm{J}\right)$
\(\mathrm{n}=\mathrm{no} .\) of photons incident/second
\(\mathrm{nE}_{\mathrm{ph}}=\mathrm{IA}\)
\(\mathrm{n}=\frac{\mathrm{IA}}{\mathrm{E}_{\mathrm{ph}}}\)
\(\mathrm{n}=\frac{\mathrm{IA}}{\left(\frac{\mathrm{hc}}{\lambda}\right)}=\frac{6.4 \times 10^{-5} \times 1}{\frac{1240}{310} \times 1.6 \times 10^{-19}}\)
\(\mathrm{n}=10^{+14}\) per second
since efficiency \(=10^{-3}\)
no. of electrons emitted \(=10^{+11}\) per second.
\(\mathrm{x}=11\)
$\left(\mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}\right.$આપેલ છે.)