Learned Indian classical vocalists do not like the accompaniment of a harmonium because
Easy
Download our app for free and get started
(d)Indian classical vocalists don’t like harmoniuim because it uses tempered scale.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A tuning fork with frequency $800 \;\mathrm{Hz}$ produces resonance in a resonance column tube with upper end open and lower end closed by water surface. Surface. Successive resonance are observed at length $9.75 \;\mathrm{cm}, 31.25\; \mathrm{cm}$ and $52.75\; \mathrm{cm} .$ The speed of sound in air is ......$m/s$
$25$ tunning forks are arranged in series in the order of decreasing frequency. Any two successive forks produce $3\, beats/sec.$ If the frequency of the first turning fork is the octave of the last fork, then the frequency of the $21^{st}$ fork is .... $Hz$
Intensity level $200 cm$ from a source of sound is $80 dB$. If there is no loss of acoustic power in air and intensity of threshold hearing is ${10^{ - 12}}W{m^{ - 2}}$ then, what is the intensity level at a distance of $400 cm$ from source .... $dB$
A pipe $17\, cm$ long is closed at one end. Which harmonic mode of the pipe resonates a $1.5\, kHz$ source ?
(Speed of sound in air $= 340\, m\, s^{-1}$)
$Assertion :$ The fundemental frequency of an open organ pipe increases as the temperature is increased.
$Reason :$ As the temperature increses, the velocity of sound increases more rapidly than length of the pipe.
Spacing between two successive nodes in a standing wave on a string is $x$ . If frequency of the standing wave is kept unchanged but tension in the string is doubled, then new spacing between successive nodes will become