MCQ
${\left( {2x - \frac{1}{{2{x^2}}}} \right)^{12}}$ ના વિસ્તરણમાં અચળપદ મેળવો.
- A$-7930$
- B$-495$
- C$495$
- ✓$7920$
Hence the required term is $^{12}{C_4}{2^8}{\left( { - \frac{1}{2}} \right)^4} = 7920$.
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| $\mathrm{x}$ | $-2$ | $-1$ | $3$ | $4$ | $6$ |
| $\mathrm{P}(\mathrm{X}=\mathrm{x})$ | $\frac{1}{5}$ | $\mathrm{a}$ | $\frac{1}{3}$ | $\frac{1}{5}$ | $\mathrm{~b}$ |
જો મધ્યક $X$ એ $2.3$ અને $X$ નું વિચરણ $\sigma^{2}$ હોય તો $100 \sigma^{2}$ ની કિમંત મેળવો.