The electronic configuration of \(Co ^{3+}\) ion
\(=[A r]_{18} 3 d^{6}\)
The splitting in octahedral field is shown below
\(C o^{3+}=3 d^{6}\left(\right.\) or \(\left.t_{2 g}^{6} e_{g}\right)\)
\(\therefore\) There is no unpaired electron, so it is diamagnetic in nature.
$(en = NH_2CH_2CH_2NH_2)$