Let A and B be two sets in the same universal set. Then , A - B = - Vidyadip

MCQ

Let $A$ and $B$ be two sets in the same universal set. Then $, A - B =$

A
$\text{A}\cap\text{B}$
B
$\text{A}'\cap\text{B}$
✓
$\text{A}\cap\text{B}'$
D
None of these.

✓

Answer

Correct option: C.

$\text{A}\cap\text{B}'$

$A - B $ belongs to those elements of $A$ that do not belong to $B$.
$\therefore\text{A} - \text{B = A}\cap\text{B}'.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Sets→Sets — all question types→Maths STD 11 Science question papers→Maharashtra Board STD 11 Science question papers→Maharashtra Board question paper generator→

Similar questions

There are 5 girls and 2 boys, then the probability that no two boys are sitting together for a photograph is

If $P ( A )= P ( B )=x$ and $P ( A \cap B )= P \left( A ^{\prime} \cap B ^{\prime}\right)=\frac{1}{3}$, then $x=$

$\lim _{x \rightarrow 0} \frac{ e ^x+ e ^{-x}-2}{x^2}=$

If ${^\text{n+1}}\text{C}_{\text{3}}=2.{^\text{n}}\text{C}_{\text{2}},$ then $n$ :

The value of sin $105^{\circ}$ is

$\lim _{x \rightarrow 0} \frac{1-\cos 2 x}{\cos 2 x-\cos 8 x}=$

If $\omega(\neq 1)$ is a cube root of unity and $(1+\omega)^7=A+B \omega$, then A and B are respectively, the numbers

$\lim _{x \rightarrow 0}\left[\frac{1}{x}-\frac{\log (1+x)}{x^2}\right]=$

The domain of definition of $f(x)=\sqrt{\frac{1-|x|}{2-|x|}}$ is

$8 \sin \frac{x}{8} \cos \frac{x}{2} \cos \frac{x}{4} \cos \frac{x}{8}$ is equal to