MCQ
Let $f(x) = \frac{x}{{1 + |x|}}$ be differentiable at . . . .
- ✓$( - \infty ,\infty )$
- B$[0,\infty ]$
- C$( - \infty ,\,0) \cup (0,\infty )$
- D$(0,\infty )$
$\Rightarrow f^{\prime}(x)=\left\{\begin{array}{ll}{\frac{x}{(1-x)^{2}},} & {x<0} \\ {\frac{x}{(1+x)^{2}}} & {x \geq 0}\end{array}\right.$
$\because f^{\prime}(x)$ exist at everywhere.
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