MCQ
Let $S = N \cup\{0\}$. Define a relation $R$ from $S$ to $R$ by :$
R =\left\{(x, y): \log _e y=x \log _e\left(\frac{2}{5}\right), x \in S, y \in R \right\}
$
Then, the sum of all the elements in the range of $R$ is equal to
  • A
    $\frac{3}{2}$
  • $\frac{5}{3}$
  • C
    $\frac{10}{9}$
  • D
    $\frac{5}{2}$

Answer

Correct option: B.
$\frac{5}{3}$
(B) $\frac{5}{3}$
$\begin{array}{ll}\text {Sol. } S =\{0,1,2,3 \ldots . .\} \\ \log _{ c } y =\log _c\left(\frac{2}{5}\right) \\ \Rightarrow y =\left(\frac{2}{5}\right)^x\end{array}$
Image
Required$
\text { Sum }=1+\left(\frac{2}{5}\right)^1+\left(\frac{2}{5}\right)^2+\left(\frac{2}{5}\right)^3+\ldots . .-=\frac{1}{1-\frac{2}{5}}=\frac{5}{3}
$

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