Let C=A+B then - Vidyadip

MCQ

Let $\vec{C}=\vec{A}+\vec{B}$ then

A
$|\vec{C}|$ is always greater then $|\vec{A}|$
✓
It is possible to have $|\vec{C}|<|\vec{A}|$ and $|\vec{C}|<\vec{B} \mid$
C
$C$ is always equal to $A+B$
D
$C$ is never equal to $A+B$

✓

Answer

Correct option: B.

It is possible to have $|\vec{C}|<|\vec{A}|$ and $|\vec{C}|<\vec{B} \mid$

(b) $\vec{C}+\vec{A}=\vec{B}$.The value of $C$ lies between $A-B$ and $A+B$$\therefore|\vec{C}|<|\vec{A}| \text { or }|\vec{C}|<|\vec{B}|$

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