Let X represent the difference between the number of heads and the number of tails obtained when a coin is tossed 6 times. What are possible values of X?
A
9, 7, 4, 0
B
0, 2, 4, 6
C
6, 7, 7, 2
D
6, 4,2, 0
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B
0, 2, 4, 6
A coin is tossed six times and X represents the difference between the number of heads and the number of tails.
$\therefore$ X(6H, 0T)=∣6 - 0∣ = 6
X(5H, 1T) = ∣5 - 1∣ = 4
X(4H, 2T) = ∣4 - 2∣ = 2
X(3H, 3T) = ∣3 - 3∣ = 0
X(2H, 4T) = ∣2 - 4∣ = 2
X(1H, 5T) = ∣1 - 5∣ = 4
X(0H, 6T) = ∣0 - 6∣ = 6
Thus, the possible values of X are 0, 2, 4 and 6.
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