Let X represent the difference between the number of heads and the number of tails obtained when a coin is tossed 6 times. What are possible values of X?
  • A
    9, 7, 4, 0
  • B
    0, 2, 4, 6
  • C
    6, 7, 7, 2
  • D
    6, 4,2, 0
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    A speaks truth in 75% cases and B seaks truth in 80% cases. Probability that they contradict each other in a statement, is
    View Solution
  • 2
    A fair coin is tossed 100 times. The probability of getting tails an odd nimber of times is:
    View Solution
  • 3
    If two events are independent, then.
    View Solution
  • 4
    A fair coin is tossed a fixed number of times. If the probability of getting seven heads is equal to that of getting nine heads, the probability of getting two heads is:
    View Solution
  • 5
    If A and B are two events, then $\text{P}(\overline{\text{A}}\cap\text{B})=$
    View Solution
  • 6
    Mark the correct alternative in the following question:
    Suppose a random variable X follows the binomial distribution with parameters n and p, where 0 < p < 1. If $\frac{\text{P(X = r})}{\text{P(X = n} -\text{r})}$ is independent of n and r, then p equals:
    View Solution
  • 7
    Three integers are chosen at random from the first 20 integers. The probability that their product is even is,
    View Solution
  • 8
    If $\text{P(B)}=\frac{3}{5},\text{P}(\text{A}|\text{B})=\frac{1}{2}$ and $\text{P}(\text{A}\cup\text{B})=\frac{4}{5},$ then $\text{P}(\text{B}|\overline{\text{A}})=$
    View Solution
  • 9
    If A and B are two events such that $\text{P(A)}\neq0$ and $\text{P(B)}\neq1,$ then $\text{P}(\overline{\text{A}}|\overline{\text{B}})=$
    View Solution
  • 10
    A bag contains 5 red and 3 blue balls are drawn at random without replacement, then the probability of getting exactly one red ball is.
    View Solution