MCQ
$\lim\limits_{\text{n}\rightarrow \infty } \frac{{\text{np}\ \text{sin}^2(\text{n}!)}}{\text{n}+1}, 0 < p < 1$ is equal to:
- ✓$0$
- B$\infty$
- C$1$
- DNone
✓
Answer
Correct option: A.
$0$
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