MCQ
$\lim_{n \rightarrow \infty}\frac{(2x-3)(3x-4)}{(4x-5)(5x-6)}=...........$
- A$0$
- B$\frac{1}{10}$
- C$\frac{1}{5}$
- ✓$\frac{3}{10}$
$\lim_{x \rightarrow \infty}\frac{(2x-3)(3x-4)}{(4x-5)(5x-6)}$
$=\lim_{x \rightarrow \infty}\frac{x^2(2-\frac{3}{x})(3-\frac{4}{x})}{x^2(4-\frac{5}{x})(5-\frac{6}{x})}$
$=\frac{(2-0)(3-0)}{(4-0)(5-0)}=\frac{6}{20}=\frac{3}{10}$
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