\(MSO_4×7H_2O\) \(= m + 32 + 64 + 126 = m + 222\)
તથા \(\,\% \,M = \frac{m}{{m +222}} \times 100 = 9.87\,\) (જે આપેલ છે.)
\(\therefore \,\,\,100\,m = 9.87\,m\, + \,222\, \times \,9.87\,\)
\(\,\therefore \,\,\,\,90.13\,m = 222\, \times \,9.87\,\,\,\)
\(\therefore \,\,m = \frac{{222 \times \,9.87}}{{90.131}} = 24.3\)
$(A)$ $CH _{3} COOH$
$(B)$ $HCHO$
$(C)$ $CH _{3} OOCH _{3}$
$(D)$ $CH _{3} CHO$