Optical isomes $= 0$
If the complex $MA_2B_2$ is $dsp^2$ hybridised then the shape of this complex is square planar
Both isomers are optically inactive due to the presence of plane of symmetry.
Optical isomers $= 0$
(પરમાણુ ક્રમાંક : $Cr = 24, Mn = 25, Fe = 26, Co = 27$)
$(i) [pt\ (en)\ Cl_2]$
$(ii)\ [pt (en)_2]\ Cl_2$
$ (iii)\ [pt (en)_2 Cl_2]\ Cl_2$
$(iv)\ [pt (CH_3)_2 Cl_2]$