Magnetic field at the centre $O$ of a square loop of side $'a'$ carrying current $I$ as shown in the figure is
A$\frac{{{\mu _0}I}}{{\sqrt 2 \pi a}}$
B$2\sqrt 2 \frac{{{\mu _0}I}}{{\pi a}}$
C$\frac{{2{\mu _0}I}}{{\pi a}}$
D
Zero
Medium
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D
Zero
d $AB$ and $DC, AD$ and $BC$ are the two current pairs. They are so situated that currents of each pair produce equal and opposite magnetic fields at the centre $O$ of the loop. Hence, the resultant magnetic field induction at the centre $O$ of the loop is zero.
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