Question
माना समीकरण $( k +1) \tan ^{2} x -\sqrt{2} \cdot \lambda \tan x =$ $(1- k ), k (\neq-1),(\lambda \in R )$ के $\alpha$ तथा $\beta$ दो वास्तविक मूल हैं। यदि $\tan ^{2}(\alpha+\beta)=50$ है, तो $\lambda$ का एक मान है
$\tan \alpha . \tan \beta=\frac{\mathrm{k}-1}{\mathrm{k}+1}$
$\tan (\alpha+\beta)=\frac{\frac{\lambda \sqrt{2}}{\mathrm{k}+1}}{1-\frac{\mathrm{k}-1}{\mathrm{k}+1}}=\frac{\lambda \sqrt{2}}{2}=\frac{\lambda}{\sqrt{2}}$
$\Rightarrow \frac{\lambda^{2}}{2}=50 \Rightarrow \lambda=10 \;and\;-10$
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Variate $x$ |
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Freq $f$ of $x$ |
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