Question
Mark out the correct options.
✓
Answer
- The total charge of the universe is constant.
The total charge (Positive + negative) oif the universe is constant.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Unit of electromotive force :
If half-life of a substance is 3.8 days and its quantity is 10.38 gm. Then substance quantity remaining left after 19 days will be(a) 0.151 gm(b) 0.32 gm(c) 1.51 gm(d) 0.16 gm
A magnetic field can be produced by:
Find the equivalent resistance across $AB$
→If the current is doubled, the deflection is also doubled in:
- A tangent galvanometer.
- A moving-coil galvanometer.
- Both.
- None.
The EMF of a cell can be defined as:
An ionic atom equivalent to hydrogen atom has wavelength equal to $1/4$ of the wavelengths of hydrogen lines. The ion will be
→Two wires $A$ and $B,$ having identical geometrical construction, are stretched from their natural length by small but equal amount. The Young's modulus of the wires are $Y_A$ and $Y_B$ whereas the densities are $\rho_\text{A}>\rho_{\text{B}^+}$ It is given that $Y_A > Y_B$ and $\rho_\text{A}>\rho_{\text{B}^+}.$ A transverse signal started at one end takes a time $t_1$ to reach the other end for $A$ and $t_2$ for $B.$
→An electromagnetic wave of frequency v = 3.0MHz passes from vacuum into a dielectric medium with permittivity ε = 4.0 . Then (a) Wavelength is doubled and the frequency remains unchanged(b) Wavelength is doubled and frequency becomes half(c) Wavelength is halved and frequency remains unchanged(d) Wavelength and frequency both remain unchanged
Assertion: In the given circuit if lamp $B$ or $C$ fuses then light emitted by lamp $A$ decreases.
Reason : Voltage on $A$ decreases.
→Reason : Voltage on $A$ decreases.