MCQ
Match List $I$ with List $II$ and select the correct answer using the codes given below the lists

 $\begin{array}{|l|l|} \hline \,\,List\,\,\,\,I\,\,(Compound) & \,\,List\,\,II\,\,(Oxidation\,\,state\,\,of\,\,N) \\ \hline (A)\,\,N{{O}_{2}} & (1)\,\,\,\,+\,\,5  \\ \hline (B)\,\,HNO  & (2)\,\,-\,\,3  \\ \hline (C)\,\,N{{H}_{3}} & (3)\,\,+\,\,4  \\ \hline (D)\,\,{{N}_{2}}{{O}_{5}} & (4)\,\,+\,\,1  \\ \hline \end{array}$

code :     $A \,\, B \,\,C \,\,D$      

  • A
    $2 \, \,\,3\, \,\,4\,\, \,1$
  • B
    $3 \, \,\,1\, \,\,2\,\, \,4$
  • $3 \, \,\,4\, \,\,2\,\, \,1$
  • D
    $2 \, \,\,3\, \,\,1\,\, \,4$

Answer

Correct option: C.
$3 \, \,\,4\, \,\,2\,\, \,1$
(c) (a) $\mathop N\limits^ * {O_2}$;$x - 4 = 0$;$x = + \,4$

     (b) $H\mathop N\limits^ * O$;$1 + x - 2 = 0$;$x = + 1$

     (c) $\mathop {N{H_3}}\limits^{ * \,\,\,\,\,\,} $; $x + 3 = 0$; $x = - 3$

     (d) ${\mathop {N_2}\limits^ *}{O_5}$; $2x - 10 = 0$;$2x = 10$; $x = \frac{{10}}{2}$; $x = 5.$

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