Question
Match the shapes $($each sides measures $2\ cm)$ in column $I$ with the corresponding perimeters in column $II$:
  Column $I$   Column $II$
$(A)$ $(i)$ $16\ cm$
$(B)$ $(ii)$ $20\ cm$
$(C)$ $(iii)$ $24\ cm$
$(D)$ $(iv)$ $28\ cm$
    $(v)$ $32\ cm$

Answer

  Column $I$   Column $II$
$(A)$ $(iv)$ $28\ cm$
$(B)$ $(i)$ $16\ cm$
$(C)$ $(ii)$ $20\ cm$
$(D)$ $(iii)$ $24\ cm$
Solution:
$a.\ $Perimeter of figure $=$ Sum of all sides
$= \text{AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LM + MN + NA}$
$= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 28\ cm$

$b.\ $Perimeter of figure $=$ Sum of all sides
$= \text{AB + BC + CD + DE + EF + FG + GH + HA}$
$= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 16\ cm$

$c.\ $Perimeter of figure $=$ Sum of all sides
$= \text{AB + BC + CD + DE + EF + FG + GH + HI + IJ + JA}$
$= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 20\ cm$​​​​​​​

$d.\ $Perimeter of figure $=$ Sum of all sides
$= \text{AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA}$
$= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 24\ cm$​​​​​​​

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