MCQ
$\mathop {\lim }\limits_{n \to \infty } \frac{1}{n}\sum\limits_{r = 1}^{2n} {\frac{r}{{\sqrt {{n^2} + {r^2}} }}} =$
- A$1 + \sqrt 5 $
- ✓$ - 1 + \sqrt 5 $
- C$ - 1 + \sqrt 2 $
- D$1 + \sqrt 2 $
$= \int_0^2 {} \frac{x}{{\sqrt {1 + {x^2}} }}\,dx = \sqrt 5 - 1$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$A = \left[ {\begin{array}{*{20}{c}}
{{{10}^{30}} + 5}&{{{10}^{20}} + 4}&{{{10}^{20}} + 6}\\
{{{10}^4} + 2}&{{{10}^8} + 7}&{{{10}^{10}} + 2n}\\
{{{10}^4} + 8}&{{{10}^6} + 4}&{{{10}^{15}} + 9}
\end{array}} \right]$ , $n \in N$, હોય તો . ..