MCQ
$\int\limits_0^\infty  {\frac{{{x^3}}}{{1 + x + 2{x^2} + 2{x^3} + {x^4} + {x^5}}}} dx$
  • A
    $\frac{{\pi  - 2}}{2}$
  • B
    $\frac{{\pi  - 1}}{2}$
  • C
    $\frac{{\pi  - 2}}{4}$
  • $\frac{{\pi  - 1}}{4}$

Answer

Correct option: D.
$\frac{{\pi  - 1}}{4}$
d
$\int_0^\infty  {\frac{{{x^3}}}{{1 + x + 2{x^2} + 2{x^3} + {x^4} + {x^5}}}} dx$

$\int_0^\infty  {\frac{{{x^3}dx}}{{(1 + x){{\left( {1 + {x^2}} \right)}^2}}}} $

put $x=\tan \theta$

$\int_0^{\frac{\pi }{2}} {\frac{{{{\tan }^3}\theta {{\sec }^2}\theta d\theta }}{{(1 + \tan \theta ){{\sec }^2}\theta  \cdot {{\sec }^2}\theta }}} $

$I=\int_{0}^{\frac{\pi}{2}} \frac{\sin ^{3} \theta d \theta}{\cos \theta+\sin \theta}$

apply king

$I=\int_{0}^{\frac{\pi}{2}} \frac{\cos ^{3} \theta d \theta}{\cos \theta+\sin \theta}$

on add $2 \mathrm{I}=\int_{0}^{\pi / 2}\left(\cos ^{2} \theta+\sin ^{2} \theta-\cos \theta \sin \theta\right)$

$=\frac{\pi}{2}+\left[\frac{\cos 2 \theta}{4}\right]_{0}^{\pi / 2}$

$I=\frac{\pi-1}{4}$

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