Question
$\mathop {\lim }\limits_{x \to \infty } \frac{{(2x - 3)(3x - 4)}}{{(4x - 5)(5x - 6)}} = $
$= \mathop {\lim }\limits_{x \to \infty } \,\,\frac{{{x^2}\left( {2 - \frac{3}{3}\,} \right)\,\left( {3 - \frac{4}{x}} \right)}}{{{x^2}\left( {4 - \frac{5}{x}} \right)\,\left( {5 - \frac{6}{x}} \right)}} = \frac{6}{{20}} = \frac{3}{{10}}$
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