MCQ
Mercury is a liquid at $0\,^o C$ because of
  • A
    very high ionisation energy
  • B
    weak metallic bonds
  • C
    high heat of hydration
  • Both $(a)$ and $(b)$

Answer

Correct option: D.
Both $(a)$ and $(b)$
d

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For the reduction of $\mathrm{NO}_3^{-}$ion in an aqueous solution, $\mathrm{E}^0$ is $+0.96 \mathrm{~V}$. Values of $\mathrm{E}^0$ for some metal ions are given below

$\mathrm{V}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{V} \ \ \ \ \mathrm{E}^0=-1.19 \mathrm{~V} $

$\mathrm{Fe}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \rightarrow \mathrm{Fe} \ \ \ \ \mathrm{E}^0=-0.04 \mathrm{~V} $

$\mathrm{Au}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \rightarrow \mathrm{Au} \ \ \ \ \mathrm{E}^0=+1.40 \mathrm{~V} $

$\mathrm{Hg}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{Hg} \ \ \ \ \mathrm{E}^0=+0.86 \mathrm{~V}$

The pair$(s)$ of metals that is$(are)$ oxidized by $\mathrm{NO}_3^{-}$in aqueous solution is$(are)$

$(A)$ $\mathrm{V}$ and $\mathrm{Hg}$ $(B)$ $\mathrm{Hg}$ and $\mathrm{Fe}$

$(C)$ $\mathrm{Fe}$ and $\mathrm{Au}$ $(D)$ $Fe$ and $V$

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